[Creo Relations] Simultaneous Equations(聯立方程式)

如何用Creo Relations解Simultaneous Equations(聯立方程式)

關於Simultaneous Equations(聯立方程式)
About Simultaneous Equations 

在Relations中的Simultaneous Equations，幾個變量(參數)或尺寸必須同時解決，因此考慮到這些規則來創建聯立方程式，幾個要點：

Relations in the Simultaneous Equations, several variables (parameters) or size must be resolved, taking into account these rules to create simultaneous equations points:

• 聯立方程式開始前，必須聲明聯立方程中使用的變量，例如，下面例子中的面積= 1000。
• 當求解聯立方程式，系統僅返回一個組結果(即使方程式的解是多於一個以上的解)。
• 您可以混用單變量關係的聯立方程式。

• Before the beginning of simultaneous equations, simultaneous equations must declare the variable used, for example, following the example of area = 1000.
• 
  
• When solving the simultaneous equations, the system returns only one set of results (even if the solution is more than one equation above solution).
• 
  
• You can mix univariate relationship simultaneous equations.

一個Model最簡單的就是算面積，已知一長方體的面積跟周長，如何求出長跟寬？

A simple example, a rectangular area with the known perimeter, how long now find wide?

Parameter:

•  Length => L
• Width => W

Conditions：

• The area equals 100
• The perimeter equals 140

Equations：

•  Area (面積) =L*W
•  Perimeter =L*2+W*2 =(L+W)*2 

Relation:
---------------------------------------------------------------------------------------------------------------
/*Simultaneous Equations
AREA = 1000
PERIMETER = 140
SOLVE
L*W = area
2*(L+W) = PERIMETER
FOR L W
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來看看，經由Relations中的Simultaneous Equations求解出來的L,W分別是多少？
From Simultaneous Equations =>   L,W?

答案是L =50 ,W=20




Tips：

• 聯立方程式要在SOLVE and FOR 間敘述。

• 出現在聯立方程中的任何變量(Variables)，不是在FOR列表中的將被解讀為常數(Constants)。

若有仔細去計算，其實這個方程式的答案有2組 (L,W) =(50,20) & (20,50);
The answer to this equation has 2 groups (L, W) = (50,20) & (20,50);

延伸題，若是W > L，Relation程式要怎麼改寫呢？
Extend, if W> L, How to rewrite this Relation?

結果在下面，動動腦試試看！







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